Genetics

Sourav Pan

in Genetics

10 Sep 2024

A chi-square test was conducted to investigate whether there is an association between a person’s favorite flavor of ice cream and their favorite toppings. Each of 200 randomly selected customers at an ice cream parlor was asked to pick their favorite flavor from vanilla, chocolate, chocolate chip, or none of these. They were also asked to pick their favorite topping from chocolate sauce, peanuts, crumbled cookies, crushed candies, or none of these. The hypothesis test had a test statistic of 24.97 with an associated p-value of 0.015. If the significance level of the test was α=0.05, which of the following is the correct decision for this hypothesis test? A) There is not convincing statistical evidence to suggest an association between favorite ice cream flavor and favorite topping. B) There is convincing statistical evidence to suggest an association between favorite ice cream flavor and favorite topping. C) There is convincing statistical evidence to suggest there is not an association between favorite ice cream flavor and favorite topping. D) There is proof that a person’s favorite ice cream topping is dependent on the person’s favorite ice cream flavor. E) There is proof that a person’s favorite ice cream topping is independent of the person’s favorite ice cream flavor.

A chi-square test was conducted to investigate whether there is an association between a person’s favorite flavor of ice cream and their favorite toppings. Each of 200 randomly selected customers at an ice cream parlor was asked to pick their favorite flavor from vanilla, chocolate, chocolate chip, or none of these. They were also asked … Read more

1 Answer

Sourav Pan

in Genetics

10 Sep 2024

Which of the following is a reason not to use a chi-square test of homogeneity to analyze a set of data? A) The data consist of one categorical variable for two or more different populations and are summarized by counts in a two-way table. B) The data were obtained through a simple random sample from a single population and summarized by counts on two categorical variables. C) The data were obtained from more than two populations to investigate whether the proportions for categorical data collected are the same. D) The data were obtained from four different regions to investigate whether the distribution of a categorical variable is different across the four regions. E) The data were obtained using a simple random sample of a population from last year and a simple random sample of the same population from this year where the data collected were categorical variables.

Which of the following is a reason not to use a chi-square test of homogeneity to analyze a set of data? A) The data consist of one categorical variable for two or more different populations and are summarized by counts in a two-way table. B) The data were obtained through a simple random sample from … Read more

1 Answer

Sourav Pan

in Genetics

10 Sep 2024

If the professionals and the students do not differ in the distributions of their responses, which of the following is equal to the expected number of students who classify the crown shapes as medium? A) 39 B) ((39)(87))/91 C) ((87)(91))/200 D) ((87)(109))/200 E) ((97)(91))/200

If the professionals and the students do not differ in the distributions of their responses, which of the following is equal to the expected number of students who classify the crown shapes as medium? A) 39 B) ((39)(87))/91 C) ((87)(91))/200 D) ((87)(109))/200 E) ((97)(91))/200

1 Answer

Sourav Pan

in Genetics

10 Sep 2024

A statistician is conducting a chi-square goodness-of-fit test and is limited by the cost, per individual, to conduct the study. The statistician selects a sample of size 39, which is the smallest sample possible that will meet the condition for large expected counts. Which of the following could not be the null hypothesis for the study? A) H0: p1=0.20, p2=0.20, p3=0.20, p4=0.20, p5=0.20 B) H0: p1=0.15, p2=0.35, p3=0.22, p4=0.15, p5=0.13 C) H0: p1=0.24, p2=0.23, p3=0.21, p4=0.18, p5=0.14 D) H0: p1=0.34, p2=0.21, p3=0.14, p4=0.15, p5=0.16 E) H0: p1=0.43, p2=0.23, p3=0.17, p4=0.09, p5=0.08

A statistician is conducting a chi-square goodness-of-fit test and is limited by the cost, per individual, to conduct the study. The statistician selects a sample of size 39, which is the smallest sample possible that will meet the condition for large expected counts. Which of the following could not be the null hypothesis for the … Read more

1 Answer

Sourav Pan

in Genetics

10 Sep 2024

l. H0: p1=p2=p3, where p1 is the proportion of the sample of sophomores that responded yes, p2 is the proportion of the sample of juniors that responded yes, and p3 is the proportion of the sample of seniors that responded yes. ll. H0: There is an association between grade level and whether or not a student regularly recycles plastic bottles. lll. H0: There is no difference in the distribution of regular recyclers across the three grade levels. A) II only B) III only C) I and II only D) I and III only E) I, II, and III

l. H0: p1=p2=p3, where p1 is the proportion of the sample of sophomores that responded yes, p2 is the proportion of the sample of juniors that responded yes, and p3 is the proportion of the sample of seniors that responded yes. ll. H0: There is an association between grade level and whether or not a … Read more

1 Answer

Sourav Pan

in Genetics

10 Sep 2024

The corresponding p-value of 0.03 means that the probability of observing a test statistic of χ2=12.4 is 0.03, assuming the null hypothesis is true. Which of the following is a valid criticism of this interpretation of the p-value? A) The null hypothesis can never be assumed to be true. B) The null hypothesis is not stated. C) The p-value is not the probability of observing 12.4 exactly. D) The significance level is not stated. E) The degrees of freedom are not stated.

The corresponding p-value of 0.03 means that the probability of observing a test statistic of χ2=12.4 is 0.03, assuming the null hypothesis is true. Which of the following is a valid criticism of this interpretation of the p-value? A) The null hypothesis can never be assumed to be true. B) The null hypothesis is not … Read more

1 Answer

Sourav Pan

in Genetics

10 Sep 2024

If children from these countries exhibit top rounding in the same proportions, what is the expected count for Malay children who show top rounding? A) 938 B) 951 C) 9 D) ((38)(51))/153 E) ((38)(9))/153

If children from these countries exhibit top rounding in the same proportions, what is the expected count for Malay children who show top rounding? A) 938 B) 951 C) 9 D) ((38)(51))/153 E) ((38)(9))/153

1 Answer

Sourav Pan

in Genetics

10 Sep 2024

A quality control specialist tests samples of the seed being packaged and uses a chi-square goodness-of-fit test to see whether the proportions in the samples match what is claimed by the company. Which of the following best describes the null hypothesis and the alternative hypothesis for the test? A) H0: p=0.20 Ha: p≠0.20 B) H0: pF=0.20, pB=0.20, pBG=0.20, pI=0.20, pNG=0.20 Ha: At least one of the proportions is different. C) H0: pF=0.55, pB=0.22, pBG=0.10, pI=0.07, pNG=0.06 Ha: At least one of the proportions is different. D) H0: All proportions are equally likely. Ha: All of the proportions are different. E) H0: There is no association between the grass-seed types. Ha: There is an association between the grass-seed types.

A quality control specialist tests samples of the seed being packaged and uses a chi-square goodness-of-fit test to see whether the proportions in the samples match what is claimed by the company. Which of the following best describes the null hypothesis and the alternative hypothesis for the test? A) H0: p=0.20 Ha: p≠0.20 B) H0: … Read more

1 Answer

Sourav Pan

in Genetics

10 Sep 2024

Jimmy believes that the shuffle feature on his music player is malfunctioning by not playing songs that meet this distribution of music types. To test this, he listens to 100 songs randomly chosen when his player is in shuffle mode and records the number of songs in each category. Which inference procedure should he use to test whether or not the shuffle feature is working correctly? A) A one-sample z-test for a population proportion B) A two-sample z-test for a difference between population proportions C) A chi-square goodness-of-fit test D) A chi-square test for homogeneity E) A matched pairs t-test for a mean difference

Jimmy believes that the shuffle feature on his music player is malfunctioning by not playing songs that meet this distribution of music types. To test this, he listens to 100 songs randomly chosen when his player is in shuffle mode and records the number of songs in each category. Which inference procedure should he use … Read more

1 Answer

Sourav Pan

in Genetics

10 Sep 2024

Ms. Harper knows that her students in a computing course can choose from one of three operating systems for the semester: Doors, Banana, or Duix. Ms. Harper wants to test the hypothesis that her students will select the operating systems in the same proportion as students in other computing courses at the university. She conducts a χ2 goodness-of-fit test and calculates χ2=3.79 with a corresponding p-value of 0.15. Which of the following is correct at a 5-percent level of significance? A) Reject the null hypothesis, since 3.79>2. B) Fail to reject the null hypothesis, since 3.79>2. C) Reject the null hypothesis, since 0.15>0.05. D) Fail to reject the null hypothesis, since 0.15>0.05. E) Reject the null hypothesis, since 0.15<3.790.

Ms. Harper knows that her students in a computing course can choose from one of three operating systems for the semester: Doors, Banana, or Duix. Ms. Harper wants to test the hypothesis that her students will select the operating systems in the same proportion as students in other computing courses at the university. She conducts … Read more

1 Answer

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