Identify the CORRECT statements: P. 5′ and 3′ ends of the transcripts can be mapped by utilizing polymerase chain reaction Q. S1 nuclease can cleave the DNA strand of a DNA-RNA hybrid R. T4 polynucleotide kinase is used for labeling 3′ end of DNA S. Baculovirus (Autographa californica) can be used as an insect expression … Read more
Biotechnology
Value of the determinant mentioned below is: Matrix=1402101101−12−121 Options: (A) 24 (B) -30 (C) -24 (D) -10
Value of the determinant mentioned below is: Matrix=1402101101−12−121 Options: (A) 24 (B) -30 (C) -24 (D) -10
HAT (hypoxanthine, aminopterin and thymidine) is used for selecting the hybridomas based on the following: I. Only hybridoma will grow since it inherited the HGPRT genes from B-cells and can synthesize DNA from hypoxanthine. II. Myeloma cells will not grow in cultures since de novo synthesis is blocked by aminopterin and due to the lack of HGPRT enzyme. Options: (A) only I is true (B) only II is true (C) both I and II are true (D) I is true and II is false
HAT (hypoxanthine, aminopterin and thymidine) is used for selecting the hybridomas based on the following: I. Only hybridoma will grow since it inherited the HGPRT genes from B-cells and can synthesize DNA from hypoxanthine. II. Myeloma cells will not grow in cultures since de novo synthesis is blocked by aminopterin and due to the lack … Read more
What will be the probability of having a colour-blind son to a woman with phenotypically normal parents and a colour-blind brother, and married to a normal man? (Assume that she has no previous children) Options: (A) 100 % (B) 50 % (C) 25 % (D) 12.5 %
What will be the probability of having a colour-blind son to a woman with phenotypically normal parents and a colour-blind brother, and married to a normal man? (Assume that she has no previous children) Options: (A) 100 % (B) 50 % (C) 25 % (D) 12.5 %
What will be the probability of having a colour-blind daughter to a phenotypically normal woman, who already had one colour-blind son, and is married to a colour-blind man? Options: (A) 75 % (B) 50 % (C) 25 % (D) 15%
What will be the probability of having a colour-blind daughter to a phenotypically normal woman, who already had one colour-blind son, and is married to a colour-blind man? Options: (A) 75 % (B) 50 % (C) 25 % (D) 15%
What would be the yield Y x/s (Kg biomass/Kg substrate)? Options: (A) 0.562 (B) 0.462 (C) 0.362 (D) 0.162
What would be the yield Y x/s (Kg biomass/Kg substrate)? Options: (A) 0.562 (B) 0.462 (C) 0.362 (D) 0.162
Structured William’s model: P. can describe the changes in intracellular components of the cell during growth Q. can not describe the death phase of the cells R. can describe the variation of size of cells in the different phases of growth S. can not describe the lag period of growth Options: (A) P, Q and S only (B) P, Q and R only (C) Q, R and S only (D) P, R and S only
Structured William’s model: P. can describe the changes in intracellular components of the cell during growth Q. can not describe the death phase of the cells R. can describe the variation of size of cells in the different phases of growth S. can not describe the lag period of growth Options: (A) P, Q and … Read more
What would be the sucrose concentration in the input feed for the output to be 45 Kg biomass h^-1? Options: (A) 3.225 Kg m^-3 (B) 4.425 Kg m^-3 (C) 5.115 Kg m^-3 (D) 6.525 Kg m^-3
What would be the sucrose concentration in the input feed for the output to be 45 Kg biomass h^-1? Options: (A) 3.225 Kg m^-3 (B) 4.425 Kg m^-3 (C) 5.115 Kg m^-3 (D) 6.525 Kg m^-3
Match items in Group I with Group II: Group I P. Glycolytic pathway Q. Eukaryotic oxidative metabolism R. Glyoxylate cycle S. Calvin cycle Group II 1. Chloroplast 2. Glyoxysomes 3. Mitochondria 4. Cytosol Options: (A) P-1, Q-2, R-3, S-4 (B) P-2, Q-3, R-4, S-1 (C) P-4, Q-3, R-2, S-1 (D) P-3, Q-4, R-1, S-2
Match items in Group I with Group II: Group I P. Glycolytic pathway Q. Eukaryotic oxidative metabolism R. Glyoxylate cycle S. Calvin cycle Group II 1. Chloroplast 2. Glyoxysomes 3. Mitochondria 4. Cytosol Options: (A) P-1, Q-2, R-3, S-4 (B) P-2, Q-3, R-4, S-1 (C) P-4, Q-3, R-2, S-1 (D) P-3, Q-4, R-1, S-2
Variance (Vx) for this population of fruit flies as calculated from the above data shall be: Options: (A) 0.85 (B) 0.25 (C) 0.061 (D) 0.08
Variance (Vx) for this population of fruit flies as calculated from the above data shall be: Options: (A) 0.85 (B) 0.25 (C) 0.061 (D) 0.08