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Determine the correctness or otherwise of the following Assertion (a) and the Reason (r) Assertion: Cytoplasmic male sterility (cms) is invariably due to defect(s) in mitochondrial function. Reason: cms can be overcome by pollinating a fertility restoring (Rf) plant with pollen from a non cms plant. (A) both (a) and (r) are true and (r) is the correct reason for (a) (B) both (a) and (r) are true and (r) is not the correct reason for (a) (C) (a) is false but (r) is true (D) (a) is true but (r) is false

Determine the correctness or otherwise of the following Assertion (a) and the Reason (r) Assertion: Cytoplasmic male sterility (cms) is invariably due to defect(s) in mitochondrial function. Reason: cms can be overcome by pollinating a fertility restoring (Rf) plant with pollen from a non cms plant. (A) both (a) and (r) are true and (r) … Read more

Thermal death of microorganisms in the liquid medium follows first order kinetics. If the initial cell concentration in the fermentation medium is 10⁸ cells / ml and the final acceptable contamination level is 10⁻³ cells, for how long should 1m³ medium be treated at temperature of 120° (thermal deactivation rate constant = 0.23 / min) to achieve acceptable load? (A) 48 min (B) 11 min (C) 110 min (D) 20 min

Thermal death of microorganisms in the liquid medium follows first order kinetics. If the initial cell concentration in the fermentation medium is 10⁸ cells / ml and the final acceptable contamination level is 10⁻³ cells, for how long should 1m³ medium be treated at temperature of 120° (thermal deactivation rate constant = 0.23 / min) … Read more

True breeding Drosophila flies with curved wings and dark bodies were mated with true breeding short wings and tan body Drosophila. The F1 progeny was observed to be with curved wings and tan body. The F1 progeny was again allowed to breed and produced flies of the following phenotype, 45 curved wings tan body, 15 short wings tan body, 16 curved wings dark body and, 6 short wings dark body. The mode of inheritance is (A) Typical Mendelian with curved wings and tan body being dominant (B) Typical non-Mendelian with curved wings and tan body not following any pattern (C) Mendelian with suppression of phenotypes (D) Mendelian with single crossover

True breeding Drosophila flies with curved wings and dark bodies were mated with true breeding short wings and tan body Drosophila. The F1 progeny was observed to be with curved wings and tan body. The F1 progeny was again allowed to breed and produced flies of the following phenotype, 45 curved wings tan body, 15 … Read more

Match Group I with Group II Group I: P. Real Time-PCR Q. 2-D Electrophoresis R. Affinity chromatography S. Microarray Group II: 1. Biochips 2. Syber Green 3. Antibody linked sephrose beads 4. Ampholytes (A) P-1, Q-2, R-4, S-3 (B) P-2, Q-3, R-4, S-1 (C) P-2, Q-4, R-3, S-1 (D) P-3, Q-2, R-1, S-4

Match Group I with Group II Group I: P. Real Time-PCR Q. 2-D Electrophoresis R. Affinity chromatography S. Microarray Group II: 1. Biochips 2. Syber Green 3. Antibody linked sephrose beads 4. Ampholytes (A) P-1, Q-2, R-4, S-3 (B) P-2, Q-3, R-4, S-1 (C) P-2, Q-4, R-3, S-1 (D) P-3, Q-2, R-1, S-4

Determine the correctness or otherwise of the following Assertion (a) and the Reason (r) Assertion: MTT assay is used to determine cell viability based on the principle of colour formation by DNA fragmentation. Reason: MTT assay is used to determine cell viability based on the colour development by converting tetrazolium soluble salt to insoluble salt. (A) both (a) and (r) are true and (r) is the correct reason for (a) (B) both (a) and (r) are true and (r) is not the correct reason for (a) (C) (a) is true but (r) is false (D) (a) is false but (r) is true

Determine the correctness or otherwise of the following Assertion (a) and the Reason (r) Assertion: MTT assay is used to determine cell viability based on the principle of colour formation by DNA fragmentation. Reason: MTT assay is used to determine cell viability based on the colour development by converting tetrazolium soluble salt to insoluble salt. … Read more

Match the following antibiotics in Group I with their mode of action in Group II Group I: P. Chloramphenicol Q. Norfloxacin R. Puromycin S. Rifampicin Group II: 1. Binds to DNA gyrase 2. Binds to RNA Polymerase 3. Inhibits peptidyl transferase 4. Mimics aminoacyl-(tRNA** (A) P-1, Q-3, R-2, S-4 (B) P-3, Q-1, R-2, S-4 (C) P-3, Q-1, R-4, S-2 (D) P-4, Q-2, R-3, S-1

Match the following antibiotics in Group I with their mode of action in Group II Group I: P. Chloramphenicol Q. Norfloxacin R. Puromycin S. Rifampicin Group II: 1. Binds to DNA gyrase 2. Binds to RNA Polymerase 3. Inhibits peptidyl transferase 4. Mimics aminoacyl-(tRNA** (A) P-1, Q-3, R-2, S-4 (B) P-3, Q-1, R-2, S-4 (C) … Read more

Match the chemicals in Group I with the possible type/class in Group II Group I: P. Picloram Q. Zeatin R. Thiamine S. Glutamine Group II: 1. Vitamin 2. Auxin 3. Amino Acid 4. Cytokinin (A) P-2, Q-4, R-1, S-3 (B) P-4, Q-1, R-2, S-3 (C) P-3, Q-1, R-2, S-4 (D) P-4, Q-2, R-1, S-3

Match the chemicals in Group I with the possible type/class in Group II Group I: P. Picloram Q. Zeatin R. Thiamine S. Glutamine Group II: 1. Vitamin 2. Auxin 3. Amino Acid 4. Cytokinin (A) P-2, Q-4, R-1, S-3 (B) P-4, Q-1, R-2, S-3 (C) P-3, Q-1, R-2, S-4 (D) P-4, Q-2, R-1, S-3

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