The turnover numbers for the enzymes, E1 and E2 are 150 s⁻¹ and 15 s⁻¹ respectively. This means (A) E1 binds to its substrate with higher affinity than E2 (B) The velocity of reactions catalyzed by E1 and E2 at their respective saturating substrate concentrations could be equal, if concentration of E2 used is 10 times that of E1 (C) The velocity of E1 catalyzed reaction is always greater than that of E2 (D) The velocity of E1 catalyzed reaction at a particular enzyme concentration and saturating substrate concentration is lower than that of E2 catalyzed reaction under the same conditions
The turnover numbers for the enzymes, E1 and E2 are 150 s⁻¹ and 15 s⁻¹ respectively. This means
(A) E1 binds to its substrate with higher affinity than E2
(B) The velocity of reactions catalyzed by E1 and E2 at their respective saturating substrate concentrations could be equal, if concentration of E2 used is 10 times that of E1
(C) The velocity of E1 catalyzed reaction is always greater than that of E2
(D) The velocity of E1 catalyzed reaction at a particular enzyme concentration and saturating substrate concentration is lower than that of E2 catalyzed reaction under the same conditions
Answered
Answer: (B) The velocity of reactions catalyzed by E1 and E2 at their respective saturating substrate concentrations could be equal, if concentration of E2 used is 10 times that of E1
The turnover number indicates how many substrate molecules an enzyme converts per second. While E1 has a higher turnover number, the reaction velocity can be equal if the concentration of E2 is adjusted accordingly.
BNO Team
