Questions and Answers

The standard deviation for the above results
(A) 2.49
(B) 2.45
(C) 2.52
(D) 2.40

The mean value of acid concentration
(A) 49.4 g/L
(B) 48.0 g/L
(C) 50.0 g/L
(D) 47.5 g/L

The value of ΔG° given K’eq as 1.7 at 23°C will be
(A) -17.19 kJ mol⁻¹
(B) -19.8 kJ mol⁻¹
(C) +52.82 kJ mol⁻¹
(D) -117.07 kJ mol⁻¹

The number of α-helical turns permeating the membrane
Common Data: The width of the lipid bilayer membrane is 30 Å. It is permeated by a protein which is a right-handed α-helix.
(A) 5.6 turns
(B) 3.5 turns
(C) 6.5 turns
(D) 5.0 turns

The ΔG° for the oxidation of NADH by FAD
Statement: The standard redox potential values for two half-reactions are given.
NAD⁺ + H⁺ + 2e⁻ ↔ NADH -0.315 V
FAD + 2H⁺ + 2e⁻ ↔ FADH₂ -0.219 V
(A) -9.25 kJ mol⁻¹
(B) -103.04 kJ mol⁻¹
(C) +51.52 kJ mol⁻¹
(D) -18.5 kJ mol⁻¹

The number of amino acid residues present in the protein
Common Data: The width of the lipid bilayer membrane is 30 Å. It is permeated by a protein which is a right-handed α-helix.
(A) 15
(B) 18
(C) 20
(D) 17

The flow rate required to result in a steady-state concentration of sucrose as 1.5 g/L in the bioreactor
Common Data: A culture of Rhizobium is grown in a chemostat (100 m³) bioreactor. The feed contains 12 g/L sucrose, Ks for the organism is 0.2 g/L and μm = 0.3 h⁻¹.
(A) 15 m³/h
(B) 26 m³/h
(C) 2.6 m³/h
(D) 150 m³/h

If Yx/s = 0.4 g/g for the above culture and steady-state cell concentration in the bioreactor is 4 g/L, the resulting substrate concentration will be
(A) 2 g/L
(B) 8 g/L
(C) 4 g/L
(D) 6 g/L

Match Group I with Group II
Group I:
P. Real Time-PCR
Q. 2-D Electrophoresis
R. Affinity chromatography
S. Microarray
Group II:
1. Biochips
2. Syber Green
3. Antibody linked sephrose beads
4. Ampholytes
(A) P-1, Q-2, R-4, S-3
(B) P-2, Q-3, R-4, S-1
(C) P-2, Q-4, R-3, S-1
(D) P-3, Q-2, R-1, S-4

True breeding Drosophila flies with curved wings and dark bodies were mated with true breeding short wings and tan body Drosophila. The F1 progeny was observed to be with curved wings and tan body. The F1 progeny was again allowed to breed and produced flies of the following phenotype, 45 curved wings tan body, 15 short wings tan body, 16 curved wings dark body and, 6 short wings dark body. The mode of inheritance is
(A) Typical Mendelian with curved wings and tan body being dominant
(B) Typical non-Mendelian with curved wings and tan body not following any pattern
(C) Mendelian with suppression of phenotypes
(D) Mendelian with single crossover