- A) (A) Typical Mendelian; curved & dark dominant
- B) (B) Typical non-Mendelian; no pattern
- C) (C) Mendelian with suppression of phenotypes
- D) (D) Mendelian with single crossover
GATE BT 2010
Total MCQ: 47
2 Q47 Match Group I with Group II: P. Real-Time PCR; Q. 2-D Electrophoresis; R. Affinity Chromatography; S. Microarray. Group II: 1. Biochips; 2. SYBR Green; 3. Antibody‐linked Sepharose beads; 4. Ampholytes.
- A) (A) P-1, Q-2, R-4, S-3
- B) (B) P-2, Q-3, R-4, S-1
- C) (C) P-2, Q-4, R-3, S-1
- D) (D) P-3, Q-2, R-1, S-4
3 Q45 Thermal death of microorganisms follows first‐order kinetics (k = 0.23 min⁻¹ at 120 °C). Initial concentration 10⁴ cells/mL; acceptable level 10³. Time to reach acceptable load?
- A) (A) 48 min
- B) (B) 11 min
- C) (C) 110 min
- D) (D) 20 min
4 Q43 Match products in Group I with microbial cultures in Group II: P. Gluconic acid, Q. Lysine, R. Dextran, S. Cellulase. Group II: 1. Leuconostoc mesenteroides; 2. Aspergillus niger; 3. Brevibacterium flavum; 4. Trichoderma reesei.
- A) (A) P-2, Q-1, R-3, S-4
- B) (B) P-1, Q-3, R-4, S-2
- C) (C) P-2, Q-3, R-1, S-4
- D) (D) P-3, Q-2, R-4, S-1
5 Q44 Assertion (A): Cytoplasmic male sterility (cms) is invariably due to defect(s) in mitochondrial function. Reason (R): cms can be overcome by pollinating a fertility restoring (Rf) plant with pollen from a non-cms plant.
- A) (A) both (A) and (R) true; (R) correct reason for (A)
- B) (B) both (A) and (R) true; (R) not correct
- C) (C) (A) true; (R) false
- D) (D) (A) false; (R) true
6 Q42 A cell has five molecules of a rare mRNA amid 4×10⁵ total mRNAs. How many clones must be screened for 99% probability of finding at least one recombinant cDNA of the rare mRNA?
- A) 4.50×10⁵
- B) 3.50×10⁵
- C) 4.20×10⁵
- D) 4.05×10⁵
7 Q40 The dissociation constant Kₙ for ligand binding to the receptor is 10⁻⁷ M. The concentration of ligand required for occupying 10% of receptors is
- A) 10⁻⁶ M
- B) 10⁻⁷ M
- C) 10⁻⁸ M
- D) 10⁻⁹ M
8 Q41 Receptor R is overexpressed in CHO cells (6×10⁷ cells). Incubated with radioligand (100 cpm/pmol), pellet counts = 1000 cpm. Assuming one ligand binds one receptor, average receptors per cell is
- A) 10⁴
- B) 10³
- C) 10⁶
- D) 10⁷
9 Q38 A mutant Gα protein with increased GTPase activity would
- A) not bind to GTP
- B) not bind to GDP
- C) show increased signaling
- D) show decreased signaling
10 Q39 Dizygotic twins are connected to a single placenta during their embryonic development. These twins
- A) have identical MHC haplotypes
- B) have identical Tₕ cells
- C) have identical T cells
- D) can accept grafts from each other