Does animal cell have vacuole?
Does animal cell have vacuole?
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The standard deviation for the above results (A) 2.49 (B) 2.45 (C) 2.52 (D) 2.40
The standard deviation for the above results (A) 2.49 (B) 2.45 (C) 2.52 (D) 2.40
The mean value of acid concentration (A) 49.4 g/L (B) 48.0 g/L (C) 50.0 g/L (D) 47.5 g/L
The mean value of acid concentration (A) 49.4 g/L (B) 48.0 g/L (C) 50.0 g/L (D) 47.5 g/L
The value of ΔG° given K’eq as 1.7 at 23°C will be (A) -17.19 kJ mol⁻¹ (B) -19.8 kJ mol⁻¹ (C) +52.82 kJ mol⁻¹ (D) -117.07 kJ mol⁻¹
The value of ΔG° given K’eq as 1.7 at 23°C will be (A) -17.19 kJ mol⁻¹ (B) -19.8 kJ mol⁻¹ (C) +52.82 kJ mol⁻¹ (D) -117.07 kJ mol⁻¹
The number of α-helical turns permeating the membrane Common Data: The width of the lipid bilayer membrane is 30 Å. It is permeated by a protein which is a right-handed α-helix. (A) 5.6 turns (B) 3.5 turns (C) 6.5 turns (D) 5.0 turns
The number of α-helical turns permeating the membrane Common Data: The width of the lipid bilayer membrane is 30 Å. It is permeated by a protein which is a right-handed α-helix. (A) 5.6 turns (B) 3.5 turns (C) 6.5 turns (D) 5.0 turns
The ΔG° for the oxidation of NADH by FAD Statement: The standard redox potential values for two half-reactions are given. NAD⁺ + H⁺ + 2e⁻ ↔ NADH -0.315 V FAD + 2H⁺ + 2e⁻ ↔ FADH₂ -0.219 V (A) -9.25 kJ mol⁻¹ (B) -103.04 kJ mol⁻¹ (C) +51.52 kJ mol⁻¹ (D) -18.5 kJ mol⁻¹
The ΔG° for the oxidation of NADH by FAD Statement: The standard redox potential values for two half-reactions are given. NAD⁺ + H⁺ + 2e⁻ ↔ NADH -0.315 V FAD + 2H⁺ + 2e⁻ ↔ FADH₂ -0.219 V (A) -9.25 kJ mol⁻¹ (B) -103.04 kJ mol⁻¹ (C) +51.52 kJ mol⁻¹ (D) -18.5 kJ mol⁻¹ … Read more
The number of amino acid residues present in the protein Common Data: The width of the lipid bilayer membrane is 30 Å. It is permeated by a protein which is a right-handed α-helix. (A) 15 (B) 18 (C) 20 (D) 17
The number of amino acid residues present in the protein Common Data: The width of the lipid bilayer membrane is 30 Å. It is permeated by a protein which is a right-handed α-helix. (A) 15 (B) 18 (C) 20 (D) 17
The flow rate required to result in a steady-state concentration of sucrose as 1.5 g/L in the bioreactor Common Data: A culture of Rhizobium is grown in a chemostat (100 m³) bioreactor. The feed contains 12 g/L sucrose, Ks for the organism is 0.2 g/L and μm = 0.3 h⁻¹. (A) 15 m³/h (B) 26 m³/h (C) 2.6 m³/h (D) 150 m³/h
The flow rate required to result in a steady-state concentration of sucrose as 1.5 g/L in the bioreactor Common Data: A culture of Rhizobium is grown in a chemostat (100 m³) bioreactor. The feed contains 12 g/L sucrose, Ks for the organism is 0.2 g/L and μm = 0.3 h⁻¹. (A) 15 m³/h (B) 26 … Read more
If Yx/s = 0.4 g/g for the above culture and steady-state cell concentration in the bioreactor is 4 g/L, the resulting substrate concentration will be (A) 2 g/L (B) 8 g/L (C) 4 g/L (D) 6 g/L
If Yx/s = 0.4 g/g for the above culture and steady-state cell concentration in the bioreactor is 4 g/L, the resulting substrate concentration will be (A) 2 g/L (B) 8 g/L (C) 4 g/L (D) 6 g/L
Match Group I with Group II Group I: P. Real Time-PCR Q. 2-D Electrophoresis R. Affinity chromatography S. Microarray Group II: 1. Biochips 2. Syber Green 3. Antibody linked sephrose beads 4. Ampholytes (A) P-1, Q-2, R-4, S-3 (B) P-2, Q-3, R-4, S-1 (C) P-2, Q-4, R-3, S-1 (D) P-3, Q-2, R-1, S-4
Match Group I with Group II Group I: P. Real Time-PCR Q. 2-D Electrophoresis R. Affinity chromatography S. Microarray Group II: 1. Biochips 2. Syber Green 3. Antibody linked sephrose beads 4. Ampholytes (A) P-1, Q-2, R-4, S-3 (B) P-2, Q-3, R-4, S-1 (C) P-2, Q-4, R-3, S-1 (D) P-3, Q-2, R-1, S-4