How many molecules of amplicons will be present in 0.1 µl of reaction? Options: (A) 102.4 (B) 1024 (C) 51.2 (D) 512
How many molecules of amplicons will be present in 0.1 µl of reaction? Options: (A) 102.4 (B) 1024 (C) 51.2 (D) 512
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How many molecules of amplicons will be generated? Options: (A) 1.024 × 10^6 (B) 1.024 × 10^7 (C) 2.048 × 10^6 (D) 2.048 × 10^7
How many molecules of amplicons will be generated? Options: (A) 1.024 × 10^6 (B) 1.024 × 10^7 (C) 2.048 × 10^6 (D) 2.048 × 10^7
The value of standard deviation (SD) will be: Options: (A) 0.061 (B) 0.25 (C) 0.61 (D) 0.85
The value of standard deviation (SD) will be: Options: (A) 0.061 (B) 0.25 (C) 0.61 (D) 0.85
Variance (Vx) for this population of fruit flies as calculated from the above data shall be: Options: (A) 0.85 (B) 0.25 (C) 0.061 (D) 0.08
Variance (Vx) for this population of fruit flies as calculated from the above data shall be: Options: (A) 0.85 (B) 0.25 (C) 0.061 (D) 0.08
What would be the sucrose concentration in the input feed for the output to be 45 Kg biomass h^-1? Options: (A) 3.225 Kg m^-3 (B) 4.425 Kg m^-3 (C) 5.115 Kg m^-3 (D) 6.525 Kg m^-3
What would be the sucrose concentration in the input feed for the output to be 45 Kg biomass h^-1? Options: (A) 3.225 Kg m^-3 (B) 4.425 Kg m^-3 (C) 5.115 Kg m^-3 (D) 6.525 Kg m^-3
What would be the yield Y x/s (Kg biomass/Kg substrate)? Options: (A) 0.562 (B) 0.462 (C) 0.362 (D) 0.162
What would be the yield Y x/s (Kg biomass/Kg substrate)? Options: (A) 0.562 (B) 0.462 (C) 0.362 (D) 0.162
What will be the probability of having a colour-blind daughter to a phenotypically normal woman, who already had one colour-blind son, and is married to a colour-blind man? Options: (A) 75 % (B) 50 % (C) 25 % (D) 15%
What will be the probability of having a colour-blind daughter to a phenotypically normal woman, who already had one colour-blind son, and is married to a colour-blind man? Options: (A) 75 % (B) 50 % (C) 25 % (D) 15%
What will be the probability of having a colour-blind son to a woman with phenotypically normal parents and a colour-blind brother, and married to a normal man? (Assume that she has no previous children) Options: (A) 100 % (B) 50 % (C) 25 % (D) 12.5 %
What will be the probability of having a colour-blind son to a woman with phenotypically normal parents and a colour-blind brother, and married to a normal man? (Assume that she has no previous children) Options: (A) 100 % (B) 50 % (C) 25 % (D) 12.5 %
HAT (hypoxanthine, aminopterin and thymidine) is used for selecting the hybridomas based on the following: I. Only hybridoma will grow since it inherited the HGPRT genes from B-cells and can synthesize DNA from hypoxanthine. II. Myeloma cells will not grow in cultures since de novo synthesis is blocked by aminopterin and due to the lack of HGPRT enzyme. Options: (A) only I is true (B) only II is true (C) both I and II are true (D) I is true and II is false
HAT (hypoxanthine, aminopterin and thymidine) is used for selecting the hybridomas based on the following: I. Only hybridoma will grow since it inherited the HGPRT genes from B-cells and can synthesize DNA from hypoxanthine. II. Myeloma cells will not grow in cultures since de novo synthesis is blocked by aminopterin and due to the lack … Read more
Value of the determinant mentioned below is: Matrix=1402101101−12−121 Options: (A) 24 (B) -30 (C) -24 (D) -10
Value of the determinant mentioned below is: Matrix=1402101101−12−121 Options: (A) 24 (B) -30 (C) -24 (D) -10